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(D) The intensity $I$ of an electromagnetic wave is related to the magnetic field amplitude $B_0$ by the formula $I = \frac{B_0^2}{2 \mu_0} c$.Given $

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$10^{-4} \ T$

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(D) The intensity $I$ of an electromagnetic wave is related to the magnetic field amplitude $B_0$ by the formula $I = \frac{B_0^2}{2 \mu_0} c$.Given $I = 10^8 \ W/m^2$,$\mu_0 = 4\pi 	imes 10^{-7} \ T \cdot m/A$,and $c = 3 	imes 10^8 \ m/s$.First,find the peak magnetic field $B_0$:$B_0^2 = \frac{2 \mu_0 I}{c} = \frac{2 	imes 4\pi 	imes 10^{-7} 	imes 10^8}{3 	imes 10^8} = \frac{8\pi}{3} 	imes 10^{-7} \approx 8.37 	imes 10^{-7} \ T^2$.$B_0 = \sqrt{8.37 	imes 10^{-7}} \approx 9.15 	imes 10^{-4} \ T$.The $rms$ value of the magnetic field is $B_{rms} = \frac{B_0}{\sqrt{2}}$.$B_{rms} = \frac{9.15 	imes 10^{-4}}{1.414} \approx 6.47 	imes 10^{-4} \ T$.Comparing this with the given options,the value is closest to $10^{-4} \ T$.

The mean intensity of radiation on the surface of the Sun is about $10^{8} \ W/m^2$. The $rms$ value of the corresponding magnetic field is closest to

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