The median class of the following frequency d | vedclass

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(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$

Vedclass · Accepted Answer

$30-40$

Vedclass · Answer

(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$cf = 4 + 5 = 9$.$3$. For class $20-30$,$cf = 9 + 9 = 18$.$4$. For class $30-40$,$cf = 18 + 10 = 28$.$5$. For class $40-50$,$cf = 28 + 14 = 42$.$6$. For class $50-60$,$cf = 42 + 8 = 50$.The total number of observations is $n = 50$.We need to find the class where the cumulative frequency is greater than or equal to $\frac{n}{2} = \frac{50}{2} = 25$.Looking at the cumulative frequencies: $4, 9, 18, 28, 42, 50$.The first cumulative frequency greater than $25$ is $28$,which corresponds to the class interval $30-40$.Therefore,the median class is $30-40$.

Class	Frequency $(f)$
$110-120$	$6$
$120-130$	$25$
$130-140$	$48$
$140-150$	$72$
$150-160$	$116$
$160-170$	$60$
$170-180$	$38$
$180-190$	$22$
$190-200$	$3$

Height (in $cm$)	Number of girls
Less than $140$	$4$
Less than $145$	$11$
Less than $150$	$29$
Less than $155$	$40$
Less than $160$	$46$
Less than $165$	$51$

Age (in years)	Number of policy holders
Below $20$	$2$
Below $25$	$6$
Below $30$	$24$
Below $35$	$45$
Below $40$	$78$
Below $45$	$89$
Below $50$	$92$
Below $55$	$98$
Below $60$	$100$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$6$	$8$	$x$	$20$	$18$	$y$	$14$

The median class of the following frequency distribution is ...........
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$
Frequency $4$ $5$ $9$ $10$ $14$ $8$

Total frequency $n = 50$.

Similar Questions

Find the median of the following frequency distribution:

Class Frequency $(f)$

$110-120$ $6$

$120-130$ $25$

$130-140$ $48$

$140-150$ $72$

$150-160$ $116$

$160-170$ $60$

$170-180$ $38$

$180-190$ $22$

$190-200$ $3$

Cumulative frequency distribution is used to calculate the $\ldots \ldots \ldots$ of a frequency distribution.

The median of the following frequency distribution is $49$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $2$ $6$ $8$ $x$ $20$ $18$ $y$ $14$

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The median class of the following frequency distribution is ...........Class$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$Frequency$4$$5$$9$$10$$14$$8$Total frequency $n = 50$.