The minimum frequency nu of continuous X-rays | vedclass

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(B) The energy of an $X$-ray photon is given by $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.In an $X$-ray tube,the maximum en

Vedclass · Accepted Answer

$
u \propto V$

Vedclass · Answer

(B) The energy of an $X$-ray photon is given by $E = h
u$,where $h$ is Planck's constant and $
u$ is the frequency.In an $X$-ray tube,the maximum energy of a photon is produced when an electron is completely stopped by the target,converting its kinetic energy into a photon.The kinetic energy gained by an electron accelerated through a potential difference $V$ is $K = eV$,where $e$ is the elementary charge.Equating the photon energy to the kinetic energy of the electron,we get $h
u = eV$.Since $h$ and $e$ are constants,it follows that $
u \propto V$.

The minimum frequency $\nu$ of continuous $X$-rays is related to the applied potential difference $V$ as

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