The mode of hybridisation of carbon in CO_2 i | vedclass

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Question

(A) The structure of $CO_2$ is $O=C=O$. In this molecule,the carbon atom forms two double bonds with two oxygen atoms. According to the steric number

Vedclass · Accepted Answer

$sp$

Vedclass · Answer

(A) The structure of $CO_2$ is $O=C=O$. In this molecule,the carbon atom forms two double bonds with two oxygen atoms. According to the steric number rule,the steric number is calculated as the number of sigma bonds plus the number of lone pairs on the central atom. For carbon in $CO_2$,there are $2$ sigma bonds and $0$ lone pairs,resulting in a steric number of $2$. $A$ steric number of $2$ corresponds to $sp$ hybridization.

List-$I$	List-$II$
$(a)$ $SF_6$	$(i)$ $sp^3d^2$
$(b)$ $PCl_5$	(ii) $sp^3d$
$(c)$ $XeF_4$	(iii) $sp^3d^3$
$(d)$ $IF_7$	(iv) $sp^3d^2$

The mode of hybridisation of carbon in $CO_2$ is

Similar Questions

Match the following:
List-$I$ List-$II$
$(a)$ $SF_6$ $(i)$ $sp^3d^2$
$(b)$ $PCl_5$ (ii) $sp^3d$
$(c)$ $XeF_4$ (iii) $sp^3d^3$
$(d)$ $IF_7$ (iv) $sp^3d^2$

The correct answer is:

Which one of the following has the maximum number of hybrid orbitals?

In which of the following compounds will the angle between two covalent bonds be the largest?

As a result of $sp$ hybridization,we get

$H - C \equiv C - C \equiv C - CH_3$
Compare the bond lengths $a$ and $b$.

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