The molar conductivity of $0.1 \ M$ $BaCl_2$ solution is $106 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ at $25^{\circ} C$. What is its conductivity?

  • A
    $1.06 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$
  • B
    $5.03 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
  • C
    $3.66 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$
  • D
    $2.6 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$

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Similar Questions

Given below are two statements :
Statement $I :$ The limiting molar conductivity of $KCl$ (strong electrolyte) is higher compared to that of $CH_{3}COOH$ (weak electrolyte).
Statement $II :$ Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements,choose the most appropriate answer from the options given below:

Conductivity of a conductor is

For a strong electrolyte,the molar conductivity is given by $\wedge _m = \wedge _m^o - 10 \sqrt{C}$. Calculate $\wedge _m$ at $0.01 \ M$ if its value at $0.16 \ M$ is $200 \ S \ cm^2 \ mol^{-1}$.

Molar conductivity of $0.02 \ M$ weak acid is $7.92 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and its molar conductivity at infinite dilution is $232.7 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. Calculate the degree of dissociation of the weak acid.

The conductivity of a centimolar solution of $KCl$ at $25^{\circ} C$ is $0.0210 \, \Omega^{-1} cm^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} C$ is $60 \, \Omega$. The value of the cell constant is $......... \, cm^{-1}$.

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