The molar conductivity of a $0.04 \text{ M}$ $AB_2$ type salt solution at $300 \text{ K}$ is $200 \text{ } \Omega^{-1} \text{ cm}^2 \text{ mol}^{-1}$. Find the conductivity.

The conductance of a $0.0015 \ M$ aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized $Pt$ electrodes. The distance between the electrodes is $120 \ cm$ with an area of cross section of $1 \ cm^2$. The conductance of this solution was found to be $5 \times 10^{-7} \ S$. The $pH$ of the solution is $4$. The value of limiting molar conductivity $\left(\Lambda_{m}^0\right)$ of this weak monobasic acid in aqueous solution is $Z \times 10^2 \ S \ cm^{2} \ mol^{-1}$. The value of $Z$ is

Write the formula to calculate conductivity by using a conductivity cell.

The specific conductance of $0.0025 \ M$ acetic acid is $5 \times 10^{-5} \ S \ cm^{-1}$ at a certain temperature. The dissociation constant of acetic acid is $...... \times 10^{-7}$. (Nearest integer) Consider limiting molar conductivity of $CH_3COOH$ as $400 \ S \ cm^2 \ mol^{-1}$.

Molar conductances of $BaCl_2, H_2SO_4$ and $HCl$ at infinite dilutions are $x_1, x_2$ and $x_3$ respectively. Equivalent conductance of $BaSO_4$ at infinite dilution will be

An electrolyte of a polymer-salt complex of poly(ethylene oxide)-LiCF$_{3}$SO$_{3}$ is shaped into a free standing circular film of $20 \ mm$ diameter and a thickness of $20 \ \mu m$. When it is sandwiched between $2$ stainless steel circular electrodes of the same diameter, this cell exhibits a conductance of $\frac{314}{5} \ S$. What is the specific conductivity of the electrolyte?