The molar heat capacity of water at constant | vedclass

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(C) Given: Molar heat capacity at constant pressure $C_p = 75 \ J \ K^{-1} \ mol^{-1}$.Heat supplied $Q = 1 \ kJ = 1000 \ J$.Mass of water $m = 100 \

Vedclass · Accepted Answer

$2.4$

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(C) Given: Molar heat capacity at constant pressure $C_p = 75 \ J \ K^{-1} \ mol^{-1}$.Heat supplied $Q = 1 \ kJ = 1000 \ J$.Mass of water $m = 100 \ g$.Molar mass of water $M = 18 \ g \ mol^{-1}$.Number of moles $n = \frac{m}{M} = \frac{100}{18} \ mol$.The formula for heat supplied at constant pressure is $Q = n 	imes C_p 	imes \Delta T$.Substituting the values: $1000 = (\frac{100}{18}) 	imes 75 	imes \Delta T$.$\Delta T = \frac{1000 	imes 18}{100 	imes 75} = \frac{180}{75} = 2.4 \ K$.

The molar heat capacity of water at constant pressure is $75 \ J \ K^{-1} \ mol^{-1}$. When $1 \ kJ$ of heat is supplied to $100 \ g$ of water,which is free to expand,the increase in temperature of water is ............... $K$.

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