The molar ionic conductances of the octahedra | vedclass

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Question

(B) In octahedral complexes,the central metal ion is coordinated with $6$ ligands.The number of ions produced by the complexes in aqueous solution is

Vedclass · Accepted Answer

$IV < III < II < I$

Vedclass · Answer

(B) In octahedral complexes,the central metal ion is coordinated with $6$ ligands.The number of ions produced by the complexes in aqueous solution is determined by their ionization:$(1) [Pt(NH_3)_5Cl]Cl_3 \rightarrow [Pt(NH_3)_5Cl]^{3+} + 3Cl^-$ ($4$ ions)$(2) [Pt(NH_3)_4Cl_2]Cl_2 \rightarrow [Pt(NH_3)_4Cl_2]^{2+} + 2Cl^-$ ($3$ ions)$(3) [Pt(NH_3)_3Cl_3]Cl \rightarrow [Pt(NH_3)_3Cl_3]^+ + Cl^-$ ($2$ ions)$(4) [Pt(NH_3)_2Cl_4] \rightarrow [Pt(NH_3)_2Cl_4]$ (Non-electrolyte,$0$ ions)Since molar conductance is directly proportional to the number of ions produced,the order is $IV < III < II < I$.

The molar ionic conductances of the octahedral complexes are in the order of:
$(1) PtCl_4 \cdot 5NH_3$
$(2) PtCl_4 \cdot 4NH_3$
$(3) PtCl_4 \cdot 3NH_3$
$(4) PtCl_4 \cdot 2NH_3$

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The molar ionic conductances of the octahedral complexes are in the order of:$(1) PtCl_4 \cdot 5NH_3$$(2) PtCl_4 \cdot 4NH_3$$(3) PtCl_4 \cdot 3NH_3$$(4) PtCl_4 \cdot 2NH_3$