The mole fraction of a solute in a 100 molal | vedclass

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(A) $100$ molal aqueous solution means there are $100$ moles of solute in $1 \ kg$ $(1000 \ g)$ of water.The number of moles of water $(n_{	ext{solve

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(A) $100$ molal aqueous solution means there are $100$ moles of solute in $1 \ kg$ $(1000 \ g)$ of water.The number of moles of water $(n_{	ext{solvent}})$ $= \frac{1000 \ g}{18 \ g/mol} = 55.56 \ mol$.The mole fraction of solute $(x_{	ext{solute}})$ $= \frac{n_{	ext{solute}}}{n_{	ext{solute}} + n_{	ext{solvent}}}$.$x_{	ext{solute}} = \frac{100}{100 + 55.56} = \frac{100}{155.56} \approx 0.6428$.$0.6428 = 64.28 	imes 10^{-2}$.Rounding off to the nearest integer,we get $64 	imes 10^{-2}$.

The mole fraction of a solute in a $100$ molal aqueous solution is $.......... \times 10^{-2}$ (Round off to the nearest integer). [Given: Atomic masses: $H = 1.0 \ u$,$O = 16.0 \ u$]

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