(B) The ion exchange reaction is: $2(C_8H_7SO_3^- Na^+) + Ca^{2+} \rightarrow (C_8H_7SO_3^-)_2 Ca^{2+} + 2Na^+$. From the stoichiometry,$2 \ mol$ of t

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(B) The ion exchange reaction is: $2(C_8H_7SO_3^- Na^+) + Ca^{2+} \rightarrow (C_8H_7SO_3^-)_2 Ca^{2+} + 2Na^+$. From the stoichiometry,$2 \ mol$ of the resin are required to exchange $1 \ mol$ of $Ca^{2+}$ ions. Therefore,$1 \ mol$ of the resin can take up $\frac{1}{2} \ mol$ of $Ca^{2+}$ ions. Given the molar mass of the resin is $206 \ g/mol$,the uptake capacity per gram of resin is $\frac{1 \ mol \ Ca^{2+}}{2 \times 206 \ g \ resin} = \frac{1}{412} \ mol/g$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

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The molecular formula of a commercial resin used for exchanging ions in water softening is $C_8H_7SO_3^- Na^+$ $(Mol. \ wt. 206)$. What would be the maximum uptake of $Ca^{2+}$ ions by the resin when expressed in mole per gram resin?

JEE MAIN 2015 All JEE MAIN

A
$\frac{2}{309}$
B
$\frac{1}{412}$
C
$\frac{1}{103}$
D
$\frac{1}{206}$

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

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The molecular formula of a commercial resin used for exchanging ions in water softening is $C_8H_7SO_3^- Na^+$ $(Mol. \ wt. 206)$. What would be the maximum uptake of $Ca^{2+}$ ions by the resin when expressed in mole per gram resin?

Similar Questions

For the combustion reaction of $1 \, mol$ of hydrocarbon $C_xH_{2y}$,the number of moles of $O_2$ required will be............

$A$ gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24 \ L$ of this mixture at $NTP$ is .............. $g$.

$19 \ g$ of a mixture containing $NaHCO_3$ and $Na_2CO_3$ on complete heating liberated $1.12 \ L$ of $CO_2$ at $STP$. The weight of the remaining solid was $15.9 \ g$. What is the weight (in $g$) of $Na_2CO_3$ in the mixture before heating?

......... $cm^3$ is the volume of $0.1 \ N \ HCl$ required to react completely with $1.0 \ g$ of pure calcium carbonate $(Ca = 40, C = 12, O = 16)$.

What volume of decimolar solution should be mixed in a solution of the same solute $(0.5 \, M, \, 200 \, mL)$ to make it $0.25 \, M$?

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