The molecular formula of a coordination compl | vedclass

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Question

(A) The reaction of the complex with $AgNO_3$ precipitates $Cl^-$ ions present outside the coordination sphere as $AgCl$. Since $1$ mole of the comple

Vedclass · Accepted Answer

$[Co(H_2O)_6]Cl_3$

Vedclass · Answer

(A) The reaction of the complex with $AgNO_3$ precipitates $Cl^-$ ions present outside the coordination sphere as $AgCl$. Since $1$ mole of the complex yields $3$ moles of $AgCl$,there must be $3$ chloride ions outside the coordination sphere. The formula $[Co(H_2O)_6]Cl_3$ dissociates as: $[Co(H_2O)_6]Cl_3(aq) \rightarrow [Co(H_2O)_6]^{3+}(aq) + 3Cl^-(aq)$ The $3Cl^-$ ions react with $AgNO_3$ to form $3$ moles of $AgCl$: $3Ag^+(aq) + 3Cl^-(aq) \rightarrow 3AgCl(s)$ Thus,the correct formula is $[Co(H_2O)_6]Cl_3$.

The molecular formula of a coordination complex is $CoH_{12}O_6Cl_3$. When one mole of this aqueous solution of the complex is reacted with an excess of aqueous $AgNO_3$ solution,$3$ moles of $AgCl$ are formed. What is the correct formula of the complex?

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