The moment of inertia of a solid cylinder of mass $M$, length $L = 2R$ and radius $R$ about an axis passing through the centre of mass and perpendicular to the axis of the cylinder is $I_1$, and about an axis passing through one end of the cylinder and perpendicular to the axis of the cylinder is $I_2$. Then:

  • A
    $I_2 < I_1$
  • B
    $I_2 - I_1 = M R^2$
  • C
    $\frac{I_2}{I_1} = \frac{19}{12}$
  • D
    $\frac{I_2}{I_1} = \frac{7}{6}$

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