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(A) The momentum $p$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lambda}$.Given:Planck's constant $h = 6.6 	imes 10^{-34}\,J\cdot

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$1.3 	imes 10^{-27}\,kg\cdot m/s$

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(A) The momentum $p$ of a photon is given by the de Broglie relation: $p = \frac{h}{\lambda}$.Given:Planck's constant $h = 6.6 	imes 10^{-34}\,J\cdot s$Wavelength $\lambda = 5000\,\mathring{A} = 5000 	imes 10^{-10}\,m = 5 	imes 10^{-7}\,m$.Substituting the values:$p = \frac{6.6 	imes 10^{-34}}{5 	imes 10^{-7}}$$p = 1.32 	imes 10^{-27}\,kg\cdot m/s$.Thus,the correct option is $A$.

The momentum of a photon with a wavelength of $5000\,\mathring{A}$ is:

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