The most appropriate reagent to distinguish b | vedclass

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(D) Acetaldehyde contains a $CH_3CO-$ group,which allows it to undergo the iodoform test in the presence of $I_2$ and $NaOH$ to form a yellow precipit

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Iodine in presence of base

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(D) Acetaldehyde contains a $CH_3CO-$ group,which allows it to undergo the iodoform test in the presence of $I_2$ and $NaOH$ to form a yellow precipitate of iodoform $(CHI_3)$.Formaldehyde does not contain a $CH_3CO-$ group and therefore does not give a positive iodoform test.Both acetaldehyde and formaldehyde give positive tests with Fehling's solution,Tollen's reagent,and Schiff's reagent,making them unsuitable for distinguishing between the two.

The most appropriate reagent to distinguish between acetaldehyde and formaldehyde is

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