The nearest distance between two atoms in cas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a $bcc$ (body-centered cubic) lattice,the atoms touch each other along the body diagonal.The length of the body diagonal is $\sqrt{3}a$,where $

Vedclass · Accepted Answer

$a\frac{\sqrt{3}}{2}$

Vedclass · Answer

(B) In a $bcc$ (body-centered cubic) lattice,the atoms touch each other along the body diagonal.The length of the body diagonal is $\sqrt{3}a$,where $a$ is the edge length of the unit cell.Since the body diagonal consists of two atomic radii $(r)$ from the corner atoms and the full diameter $(2r)$ of the central atom,we have $4r = \sqrt{3}a$,which gives the atomic radius $r = \frac{\sqrt{3}a}{4}$.The nearest distance $(d)$ between two atoms is the distance between a corner atom and the central atom,which is $2r$.Therefore,$d = 2 	imes \left( \frac{\sqrt{3}a}{4} ight) = \frac{\sqrt{3}a}{2}$.

The nearest distance between two atoms in case of a $bcc$ lattice is equal to

Similar Questions

The maximum potential energy due to electrostatic repulsion between two hydrogen nuclei is nearly (radius of the nucleus $= 1.1 \ Fermi$). $\left[ \frac{1}{4 \pi \epsilon_0} = 9 \times 10^9 \ N \ m^2 \ C^{-2} \right]$ (in $MeV$)

$A$ free neutron decays into a proton,but a free proton does not decay into a neutron. This is because

The coordination number of $Cu$ is

$1 \, \text{atomic mass unit (amu)}$ is equal to:

The radius of a Germanium $(Ge)$ nucleus is twice the radius of a $^9_4Be$ nucleus. The number of nucleons in $Ge$ is ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module