The negation of p rightarrow (sim p vee q) is | vedclass

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(D) To find the negation of $p \rightarrow (\sim p \vee q)$,we use the logical equivalence $\sim(A \rightarrow B) \equiv A \wedge \sim B$.Here,$A = p$

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$p \wedge \sim q$

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(D) To find the negation of $p \rightarrow (\sim p \vee q)$,we use the logical equivalence $\sim(A \rightarrow B) \equiv A \wedge \sim B$.Here,$A = p$ and $B = (\sim p \vee q)$.Therefore,$\sim[p \rightarrow (\sim p \vee q)] \equiv p \wedge \sim(\sim p \vee q)$.Using De Morgan's Law,$\sim(\sim p \vee q) \equiv \sim(\sim p) \wedge \sim q \equiv p \wedge \sim q$.Substituting this back,we get $p \wedge (p \wedge \sim q)$.Since $p \wedge p \equiv p$,the expression simplifies to $p \wedge \sim q$.Thus,the negation is $p \wedge \sim q$.

The negation of $p \rightarrow (\sim p \vee q)$ is

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