The negation of the inverse of sim p rightarr | vedclass

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(D) Given statement: $\sim p \rightarrow q$. The inverse of a statement $A \rightarrow B$ is $\sim A \rightarrow \sim B$. Therefore,the inverse of $\s

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$p \wedge q$

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(D) Given statement: $\sim p \rightarrow q$. The inverse of a statement $A \rightarrow B$ is $\sim A \rightarrow \sim B$. Therefore,the inverse of $\sim p \rightarrow q$ is $\sim(\sim p) \rightarrow \sim q$,which simplifies to $p \rightarrow \sim q$. The negation of an implication $A \rightarrow B$ is $A \wedge (\sim B)$. Thus,the negation of $p \rightarrow \sim q$ is $p \wedge \sim(\sim q)$,which simplifies to $p \wedge q$.

The negation of the inverse of $\sim p \rightarrow q$ is

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