The negation of the statement pattern sim s v | vedclass

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Question

(A) We need to find the negation of the statement $\sim s \vee (\sim r \wedge s)$.Applying the negation operator:$\sim (\sim s \vee (\sim r \wedge s))

Vedclass · Accepted Answer

$s \wedge r$

Vedclass · Answer

(A) We need to find the negation of the statement $\sim s \vee (\sim r \wedge s)$.Applying the negation operator:$\sim (\sim s \vee (\sim r \wedge s))$Using De Morgan's law,$\sim (p \vee q) \equiv \sim p \wedge \sim q$:$\equiv s \wedge \sim (\sim r \wedge s)$Using De Morgan's law again,$\sim (p \wedge q) \equiv \sim p \vee \sim q$:$\equiv s \wedge (r \vee \sim s)$Using the Distributive law,$p \wedge (q \vee r) \equiv (p \wedge q) \vee (p \wedge r)$:$\equiv (s \wedge r) \vee (s \wedge \sim s)$Using the Complement law,$s \wedge \sim s \equiv F$:$\equiv (s \wedge r) \vee F$Using the Identity law,$p \vee F \equiv p$:$\equiv s \wedge r$

The negation of the statement pattern $\sim s \vee (\sim r \wedge s)$ is equivalent to

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