The net current flowing in the given circuit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a steady state,the capacitor acts as an open circuit. Therefore,no current flows through the branch containing the capacitor.Looking at the cir

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) In a steady state,the capacitor acts as an open circuit. Therefore,no current flows through the branch containing the capacitor.Looking at the circuit,the $2 	ext{V}$ battery is connected in parallel with the $4 \Omega$ resistor.The current through the $4 \Omega$ resistor is $I_1 = \frac{2 	ext{V}}{4 \Omega} = 0.5 	ext{A}$.The rest of the circuit (the branch with $2 \Omega$,$3 \Omega$,$6 \Omega$ resistors) is also connected in parallel to the battery.The equivalent resistance of the $3 \Omega$ and $6 \Omega$ resistors in parallel is $R_p = \frac{3 	imes 6}{3 + 6} = 2 \Omega$.This $R_p$ is in series with the $2 \Omega$ resistor,so the total resistance of this branch is $R_{branch} = 2 \Omega + 2 \Omega = 4 \Omega$.The current through this branch is $I_2 = \frac{2 	ext{V}}{4 \Omega} = 0.5 	ext{A}$.The total current flowing from the battery is $I = I_1 + I_2 = 0.5 	ext{A} + 0.5 	ext{A} = 1 	ext{A}$.

The net current flowing in the given circuit is . . . . . . $\text{A}$.

Similar Questions

$A$ coil takes $15\,min$ to boil a certain amount of water,and another coil takes $20\,min$ for the same process. What is the time taken to boil the same amount of water when both coils are connected in series?

Pick out the wrong statement.

Find the percentage error in the reading of the voltmeter shown in the circuit. (in $\%$)

Total $emf$ produced in a thermocouple does not depend on

Vedclass Test Series

Exam Paper Generator

Online Exam Module