The nitration will mainly take place at posit | vedclass

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(D) The given molecule is a flavanone derivative. It contains two benzene rings: one fused to a pyranone ring and another attached to the pyranone rin

Vedclass · Accepted Answer

$4$

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(D) The given molecule is a flavanone derivative. It contains two benzene rings: one fused to a pyranone ring and another attached to the pyranone ring.Nitration is an electrophilic aromatic substitution reaction. The reactivity of the benzene ring towards electrophiles depends on the electron density.The benzene ring attached to the pyranone ring (the right-hand side ring) is deactivated by the electron-withdrawing effect of the carbonyl group and the oxygen atom, making it less reactive.The benzene ring fused to the pyranone ring (the left-hand side ring) is activated by the lone pair of electrons on the oxygen atom, which shows a $+M$ effect (mesomeric effect).This $+M$ effect increases the electron density at the ortho and para positions relative to the oxygen atom.Positions $3$ and $4$ are on this activated ring. Position $3$ is meta to the oxygen atom, and position $4$ is para to the oxygen atom.Due to the $+M$ effect, the para position $(4)$ is highly activated and is the most favored site for electrophilic substitution.Therefore, the nitration will mainly take place at position $4$.

The nitration will mainly take place at position $.$

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