The normality of 10 V (volume) hydrogen perox | vedclass

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Question

(C) The relationship between volume strength and normality is given by the formula: $	ext{Normality} = \frac{	ext{Volume strength}}{5.6}$.Given,volu

Vedclass · Accepted Answer

$1.78$

Vedclass · Answer

(C) The relationship between volume strength and normality is given by the formula: $	ext{Normality} = \frac{	ext{Volume strength}}{5.6}$.Given,volume strength = $10$ $V$.Therefore,$	ext{Normality} = \frac{10}{5.6} \approx 1.786 \ 	ext{N}$.Rounding to the nearest provided option,the answer is $1.78$.

The normality of $10$ $V$ (volume) hydrogen peroxide is:

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