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(D) According to Faraday's law of electromagnetic induction,the magnitude of induced $EMF$ is given by $\varepsilon = -\frac{d\phi}{dt}$. In the first

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Higher value anticlockwise,Low value clockwise

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(D) According to Faraday's law of electromagnetic induction,the magnitude of induced $EMF$ is given by $\varepsilon = -\frac{d\phi}{dt}$. In the first case,the north pole is moved swiftly downward,meaning the rate of change of magnetic flux $(d\phi/dt)$ is high,resulting in a higher magnitude of induced current. By Lenz's law,the coil will oppose the approach of the north pole by creating a north pole on its upper face,which corresponds to an anticlockwise direction of current. In the second case,the magnet is raised slowly,meaning the rate of change of magnetic flux is low,resulting in a lower magnitude of induced current. By Lenz's law,the coil will oppose the recession of the north pole by creating a south pole on its upper face,which corresponds to a clockwise direction of current. Therefore,the first case has a higher value of anticlockwise current,and the second case has a low value of clockwise current.

The north pole of a bar magnet is moved swiftly downward towards a closed coil and then a second time it is raised upwards slowly. The magnitude and direction of the induced currents in the two cases will be of:

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