(C) The process described is electron capture, where the nucleus $^{64}_{29}Cu$ captures an orbital electron $(-1e^0)$.In this process, the atomic num

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(C) The process described is electron capture, where the nucleus $^{64}_{29}Cu$ captures an orbital electron $(-1e^0)$.In this process, the atomic number decreases by $1$ while the mass number remains constant.The nuclear equation is: $^{64}_{29}Cu + _{-1}e^0 \longrightarrow ^{64}_{28}Ni$.Thus, the product is $^{64}_{28}Ni$.

Class 12 Chemistry Nuclear Chemistry Nucleus (Stability and Reaction)

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The nucleus $^{64}_{29}Cu$ accepts an orbital electron to yield:

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A
$^{65}_{28}Ni$
B
$^{64}_{30}Zn$
C
$^{64}_{28}Ni$
D
$^{65}_{30}Zn$

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Nuclear Chemistry

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The nucleus $^{64}_{29}Cu$ accepts an orbital electron to yield:

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