The number of 4f electrons in the ground stat | vedclass

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(A) The electronic configuration of neutral Gadolinium $(Gd)$ with atomic number $64$ is $[Xe] 4f^7 5d^1 6s^2$.When $Gd$ forms a $Gd^{2+}$ ion,it lose

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$7$

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(A) The electronic configuration of neutral Gadolinium $(Gd)$ with atomic number $64$ is $[Xe] 4f^7 5d^1 6s^2$.When $Gd$ forms a $Gd^{2+}$ ion,it loses two electrons from the outermost $6s$ orbital.Therefore,the electronic configuration of $Gd^{2+}$ becomes $[Xe] 4f^7 5d^1 6s^0$.Thus,the number of $4f$ electrons in the ground state electronic configuration of $Gd^{2+}$ is $7$.

The number of $4f$ electrons in the ground state electronic configuration of $Gd^{2+}$ is ........ .
[Atomic number of $Gd=64$]

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The number of $4f$ electrons in the ground state electronic configuration of $Gd^{2+}$ is ........ .[Atomic number of $Gd=64$]