The number of -CH_2- (methylene) groups in th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The starting material is $oct-4-ene$ $(CH_3CH_2CH_2CH=CHCH_2CH_2CH_3)$.Step $1$: Ozonolysis $(O_3, Zn/H_2O)$ cleaves the double bond to form two m

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) The starting material is $oct-4-ene$ $(CH_3CH_2CH_2CH=CHCH_2CH_2CH_3)$.Step $1$: Ozonolysis $(O_3, Zn/H_2O)$ cleaves the double bond to form two moles of butanal $(CH_3CH_2CH_2CHO)$.Step $2$: Oxidation with $KMnO_4$ converts butanal into butanoic acid $(CH_3CH_2CH_2COOH)$.Step $3$: Kolbe's electrolysis of the sodium salt of butanoic acid $(CH_3CH_2CH_2COONa)$ leads to the coupling of the propyl radical $(CH_3CH_2CH_2\cdot)$ to form $n-hexane$ $(CH_3CH_2CH_2CH_2CH_2CH_3)$.Step $4$: Aromatization of $n-hexane$ using $Cr_2O_3$ at $770 \ K$ and $20 \ atm$ yields benzene $(C_6H_6)$.In the final product,benzene,there are no $-CH_2-$ (methylene) groups as all carbon atoms are $sp^2$ hybridized and part of the aromatic ring.Therefore,the number of $-CH_2-$ groups is $0$.

The number of $-CH_2-$ (methylene) groups in the product formed from the following reaction sequence is. . . . . . .

Similar Questions

Write down the conditions for a compound to possess aromaticity.

The reagent used in Friedel-Crafts reaction is:

Which one of the following gives a sooty flame on combustion?

The product obtained by the hydrogenation of $1 \ mol$ of benzene with $3 \ mol$ of $H_2$ in the presence of a $Ni$ catalyst at high temperature is...

Product $(A)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module