The number of antibonding electron pairs in O | vedclass

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(A) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$ electrons.The molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \si

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$ electrons.The molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.The antibonding orbitals are $\sigma^* 1s$,$\sigma^* 2s$,$\pi^* 2p_x$,and $\pi^* 2p_y$.Each of these four antibonding orbitals contains $2$ electrons,forming $4$ pairs.Thus,the number of antibonding electron pairs is $4$.

The number of antibonding electron pairs in $O_2^{2-}$ molecular ion on the basis of molecular orbital theory is

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