The number of atoms in 4.25 g of NH_3 is app | vedclass

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(D) The molar mass of $NH_3$ is $14 + (3 	imes 1) = 17 \ g/mol$.Number of moles of $NH_3 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{4.25 \

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$6 	imes 10^{23}$

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(D) The molar mass of $NH_3$ is $14 + (3 	imes 1) = 17 \ g/mol$.Number of moles of $NH_3 = \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{4.25 \ g}{17 \ g/mol} = 0.25 \ mol$.Number of molecules of $NH_3 = 0.25 	imes 6.022 	imes 10^{23} \approx 1.5055 	imes 10^{23}$ molecules.Each molecule of $NH_3$ contains $4$ atoms ($1$ nitrogen atom and $3$ hydrogen atoms).Total number of atoms $= 1.5055 	imes 10^{23} 	imes 4 = 6.022 	imes 10^{23} \approx 6 	imes 10^{23}$.

The number of atoms in $4.25 \ g$ of $NH_3$ is approximately

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