The number of atoms in 4.25 text{ g} of NH_3 | vedclass

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(D) The molar mass of $NH_3 = 14 + (3 	imes 1) = 17 	ext{ g/mol}$.Number of moles of $NH_3 = \frac{4.25 	ext{ g}}{17 	ext{ g/mol}} = 0.25 	ext{ m

Vedclass · Accepted Answer

$6 	imes 10^{23}$

Vedclass · Answer

(D) The molar mass of $NH_3 = 14 + (3 	imes 1) = 17 	ext{ g/mol}$.Number of moles of $NH_3 = \frac{4.25 	ext{ g}}{17 	ext{ g/mol}} = 0.25 	ext{ mol}$.Number of molecules of $NH_3 = 0.25 	imes 6.022 	imes 10^{23} \approx 1.5055 	imes 10^{23}$.Each molecule of $NH_3$ contains $4$ atoms ($1$ nitrogen and $3$ hydrogen).Total number of atoms $= 4 	imes 1.5055 	imes 10^{23} \approx 6.022 	imes 10^{23} \approx 6 	imes 10^{23}$.

The number of atoms in $4.25 \text{ g}$ of $NH_3$ is approximately

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