The number of electrons delivered at the cathode during electrolysis by a current of $1 \ A$ in $60 \ s$ is (charge on electron $= 1.60 \times 10^{-19} \ C$)
- A$6 \times 10^{23}$
- B$6 \times 10^{20}$
- C$3.75 \times 10^{20}$
- D$7.48 \times 10^{23}$
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