The number of electrons flowing per second in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The power $P$ of the bulb is given by $P = V \cdot I$.Given $P = 110 \,W$ and $V = 220 \,V$.Substituting the values,$110 = 220 	imes I$.Therefore

Vedclass · Accepted Answer

$31.25 	imes 10^{17}$

Vedclass · Answer

(A) The power $P$ of the bulb is given by $P = V \cdot I$.Given $P = 110 \,W$ and $V = 220 \,V$.Substituting the values,$110 = 220 	imes I$.Therefore,the current $I = \frac{110}{220} = 0.5 \,A$.The current $I$ is defined as the rate of flow of charge,$I = \frac{q}{t} = \frac{n \cdot e}{t}$,where $n$ is the number of electrons and $e$ is the elementary charge.We need to find the number of electrons per second,which is $\frac{n}{t} = \frac{I}{e}$.Substituting $I = 0.5 \,A$ and $e = 1.6 	imes 10^{-19} \,C$:$\frac{n}{t} = \frac{0.5}{1.6 	imes 10^{-19}} = \frac{5}{16} 	imes 10^{19} = 0.3125 	imes 10^{19} = 31.25 	imes 10^{17}$ electrons per second.

The number of electrons flowing per second in the filament of a $110 \,W$ bulb operating at $220 \,V$ is : (Given $e=1.6 \times 10^{-19} \,C$ )

Similar Questions

An electrical power line, having a total resistance of $2 \, \Omega$, delivers $1 \, kW$ at $220 \, V$. The efficiency of the transmission line is approximately $....... \%$.

An electric bulb is marked $100\ W, 230\ V$. If the supply voltage drops to $115\ V$,how much heat (in $J$) is produced by the bulb in $20\ min$?

Which device can convert all electrical energy into heat?

In a building,there are $15$ bulbs of $45 \; W$,$15$ bulbs of $100 \; W$,$15$ small fans of $10 \; W$,and $2$ heaters of $1 \; kW$. The voltage of the electric main is $220 \; V$. The minimum fuse capacity (rated value) of the building will be: .......... $A$

Two electric bulbs have tungsten filaments of the same length. If one of them is rated $60\ W$ and the other $100\ W$,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module