The number of electrons required to deposit $1 \ g$ atom of aluminium (at. wt. $= 27$) from a solution of aluminium chloride will be ............ $N$ (where $N$ is Avogadro's number).

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

$A$ solution of aluminium chloride is electrolysed for $30$ minutes using a current of $2 \ A$. The amount of the aluminium deposited at the cathode is $.................$
[Given : molar mass of aluminium and chlorine are $27 \ g \ mol^{-1}$ and $35.5 \ g \ mol^{-1}$ respectively,Faraday constant $= 96500 \ C \ mol^{-1}$]. (in $g$)

Which equation represents Faraday's first law of electrolysis? ($m \rightarrow$ mass,$c \rightarrow$ current,$t \rightarrow$ time,$z \rightarrow$ electrochemical equivalent)

Copper sulphate solution is electrolysed between two platinum electrodes. $A$ current is passed until $1.6 \ g$ of oxygen is liberated at the anode. The amount of copper deposited at the cathode during the same period is .............. $g$ [At. mass of $Cu = 63.6$]

During electrolysis of an aqueous solution of $Na_{2}SO_{4}$,$2.4 \, L$ of $O_{2}$ at $STP$ was liberated at the anode. The volume of $H_{2}$ at $STP$ liberated at the cathode is ............. $L$.

The mass of copper deposited from a solution of $CuSO_4$ by passage of $5 \ A$ current for $965 \ s$ is ............ $g$ (Mol. wt. of Copper $= 63.5$)

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