The number of elements among O, Cl, F, N, P, | vedclass

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(C) $K$ $(+1)$,$Sc$ $(+3)$,and $F$ $(-1)$ show only one non-zero oxidation state.The oxidation states of $O$ are $-1, -2, +2$.The oxidation states of

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$6$

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(C) $K$ $(+1)$,$Sc$ $(+3)$,and $F$ $(-1)$ show only one non-zero oxidation state.The oxidation states of $O$ are $-1, -2, +2$.The oxidation states of $Cl$ range from $-1$ to $+7$.The oxidation states of $N$ and $P$ range from $-3$ to $+5$.The oxidation states of $Sn$ range from $+2$ to $+4$.The oxidation states of $Ti$ are $+2, +3, +4$.Thus,the elements showing more than one non-zero oxidation state are $O, Cl, N, P, Sn, Ti$.Therefore,the total number of such elements is $6$.The correct option is $C$.

The number of elements among $O, Cl, F, N, P, Sn, Ti, K, Sc$ which show more than one non-zero oxidation state is:

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