(C) For the $4^{th}$ period,the principal quantum number is $n=4$. Orbitals being filled are $4s$,$3d$,and $4p$. The number of electrons that can be a

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(C) For the $4^{th}$ period,the principal quantum number is $n=4$. Orbitals being filled are $4s$,$3d$,and $4p$. The number of electrons that can be accommodated in these orbitals is $2 (4s) + 10 (3d) + 6 (4p) = 18$. Therefore,the number of elements in the $4^{th}$ period is $18$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Extended or long form of periodic table

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The number of elements present in the fourth period is

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$32$
B
$8$
C
$18$
D
$2$

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Class 11

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Classification of Elements and Periodicity in Properties

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Extended or long form of periodic table

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The number of elements present in the fourth period is

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