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(C) The complex is $[Co(AB)_2Cl_2]^{-}$,where $AB$ is an unsymmetrical bidentate ligand $(H_2NCH_2CH_2O^{-})$. Here,$A$ represents the $N$ donor atom

Vedclass · Accepted Answer

$5$

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(C) The complex is $[Co(AB)_2Cl_2]^{-}$,where $AB$ is an unsymmetrical bidentate ligand $(H_2NCH_2CH_2O^{-})$. Here,$A$ represents the $N$ donor atom and $B$ represents the $O$ donor atom. For an octahedral complex of the type $[M(AB)_2X_2]$,the possible geometric isomers are: $1$. Trans-$Cl$,Trans-$A$,Trans-$B$ $2$. Trans-$Cl$,Cis-$A$,Cis-$B$ $3$. Cis-$Cl$,Trans-$A$,Cis-$B$ $4$. Cis-$Cl$,Cis-$A$,Trans-$B$ $5$. Cis-$Cl$,Cis-$A$,Cis-$B$ Thus,there are $5$ possible geometric isomers.

The number of geometric isomers possible for the complex $[CoL_2 Cl_2]^{-}$ where $L = H_2NCH_2CH_2O^{-}$ is

Similar Questions

$[Co(NH_3)_4(NO_2)_2]Cl$ exhibits

Which of the following will be able to show geometrical isomerism?

Assertion : $[Co(NO_2)_3(NH_3)_3]$ does not show optical isomerism.
Reason : It has a plane of symmetry.

The metal complex that is diamagnetic is (Atomic number: $Fe = 26, Cu = 29$)

Identify the homoleptic complexes with an odd number of $d$ electrons in the central metal ion.
$(A) \ [FeO_4]^{2-}$
$(B) \ [Fe(CN)_6]^{3-}$
$(C) \ [Fe(CN)_5 NO]^{2-}$
$(D) \ [CoCl_4]^{2-}$
$(E) \ [Co(H_2O)_3 F_3]$
Choose the correct answer from the options given below $:$

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