The number of gram atoms of oxygen present in | vedclass

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(B) The chemical formula of the compound is $(COOH)_2 \cdot 2H_2O$. One molecule of $(COOH)_2 \cdot 2H_2O$ contains $6$ oxygen atoms ($4$ from the oxa

Vedclass · Accepted Answer

$1.8$

Vedclass · Answer

(B) The chemical formula of the compound is $(COOH)_2 \cdot 2H_2O$. One molecule of $(COOH)_2 \cdot 2H_2O$ contains $6$ oxygen atoms ($4$ from the oxalic acid part and $2$ from the water of crystallization). Therefore,$1 \ mol$ of $(COOH)_2 \cdot 2H_2O$ contains $6 \ mol$ of oxygen atoms. For $0.3 \ mol$ of $(COOH)_2 \cdot 2H_2O$,the number of moles of oxygen atoms is $0.3 	imes 6 = 1.8 \ mol$. Since $1 \ mol$ of atoms is equivalent to $1 \ gram \ atom$,the number of gram atoms of oxygen is $1.8$.

List-$I$ (Mass of substance)	List-$II$ (Number of atoms)
$A$. $1.8 \text{ mg}$ water	$I$. $2 \times 10^{-4} \times N_{A}$
$B$. $9.8 \text{ mg}$ sulphuric acid	$II$. $1.5 \times 10^{-4} \times N_{A}$
$C$. $1.8 \text{ mg}$ carbon	$III$. $3 \times 10^{-4} \times N_{A}$
$D$. $5.85 \text{ mg}$ salt (NaCl)	$IV$. $7 \times 10^{-4} \times N_{A}$

The number of gram atoms of oxygen present in $0.3 \ mol$ of $(COOH)_2 \cdot 2H_2O$ is

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