The number of hydrogen atoms present in 5.4 | vedclass

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Question

(B) The molar mass of urea $(CO(NH_{2})_{2})$ is $60 \ g \ mol^{-1}$.Number of moles of urea = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{5.

Vedclass · Accepted Answer

$2.168 	imes 10^{23}$

Vedclass · Answer

(B) The molar mass of urea $(CO(NH_{2})_{2})$ is $60 \ g \ mol^{-1}$.Number of moles of urea = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{5.4 \ g}{60 \ g \ mol^{-1}} = 0.09 \ mol$.Each molecule of urea contains $4$ hydrogen atoms.Therefore, the number of moles of hydrogen atoms = $0.09 \ mol 	imes 4 = 0.36 \ mol$.Number of hydrogen atoms = $	ext{Number of moles} 	imes N_{A} = 0.36 	imes 6.022 	imes 10^{23} = 2.168 	imes 10^{23}$ atoms.

The number of hydrogen atoms present in $5.4 \ g$ of urea is : (Given : Molar mass of urea: $60 \ g \ mol^{-1}$, $N_{A} = 6.022 \times 10^{23} \ particles \ mol^{-1}$)

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