The number of molecules and moles in 2.8375 | vedclass

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(D) At $STP$,the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$.Number of moles of $O_2 = \frac{	ext{Volume at } STP}{22.7 \ L \ mol^{-1}} = \

Vedclass · Accepted Answer

$7.527 	imes 10^{22}$ and $0.125 \ mol$

Vedclass · Answer

(D) At $STP$,the molar volume of an ideal gas is $22.7 \ L \ mol^{-1}$.Number of moles of $O_2 = \frac{	ext{Volume at } STP}{22.7 \ L \ mol^{-1}} = \frac{2.8375 \ L}{22.7 \ L \ mol^{-1}} = 0.125 \ mol$.Number of molecules $= 	ext{Number of moles} 	imes N_A = 0.125 	imes 6.022 	imes 10^{23} \ mol^{-1} = 7.5275 	imes 10^{22}$ molecules.Therefore,the values are $7.527 	imes 10^{22}$ molecules and $0.125 \ mol$.

The number of molecules and moles in $2.8375 \ L$ of $O_2$ at $STP$ are respectively

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