The number of moles of $KMnO_4$ reduced by one mole of $KI$ in alkaline medium is
- A$1/5$
- B$5$
- C$1$
- D$2$
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In an alkaline solution,$ClO_2$ oxidizes $H_2O_2$ to $O_2$ and is itself reduced to $Cl^-$. How many moles of $H_2O_2$ will be oxidized by $1 \ mol$ of $ClO_2$?
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