(A) $I$. Moles of $NaOH = \text{Molarity} \times \text{Volume (L)} = 0.2 \times 0.5 = 0.1 \ mol$.$II$. For $H_2SO_4$,$n$-factor $= 2$. Molarity $= \fr

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) $I$. Moles of $NaOH = \text{Molarity} \times \text{Volume (L)} = 0.2 \times 0.5 = 0.1 \ mol$.$II$. For $H_2SO_4$,$n$-factor $= 2$. Molarity $= \frac{\text{Normality}}{n-\text{factor}} = \frac{0.1}{2} = 0.05 \ M$.Moles of $H_2SO_4 = 0.05 \times 0.2 = 0.01 \ mol$.$III$. Molar mass of urea $(NH_2CONH_2) = 60 \ g/mol$.Moles of urea $= \frac{\text{Given mass}}{\text{Molar mass}} = \frac{6}{60} = 0.1 \ mol$.Thus,the number of moles are $0.1, 0.01, 0.1$. Hence,option $(A)$ is correct.

Class 11 Chemistry Some Basic Concepts of Chemistry Mix Examples of Some Basic Concept of Chemistry

Easy

The number of moles of solute present in the solutions of $I$,$II$ and $III$ is respectively:
$I$. $500 \ mL$ of $0.2 \ M \ NaOH$
$II$. $200 \ mL$ of $0.1 \ N \ H_2SO_4$
$III$. $6 \ g$ of urea in $1 \ kg$ of water

AP EAMCET 2019 All AP EAMCET

A
$0.1, 0.01, 0.1$
B
$0.1, 0.02, 0.1$
C
$0.2, 0.01, 0.1$
D
$0.1, 0.01, 0.2$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Some Basic Concepts of Chemistry

Subtopic

Mix Examples of Some Basic Concept of Chemistry

Previous Year

AP EAMCET 2019 Paper All AP EAMCET years →

$4 \ g$ equimolar mixture of $NaOH$ and $Na_{2}CO_{3}$ contains $x \ g$ of $NaOH$ and $y \ g$ of $Na_{2}CO_{3}$. The value of $x$ is $..... \ g$. (Nearest integer)

DifficultJEE MAIN 2021

View Solution

If one liter of air is repeatedly passed over heated copper and magnesium until no further reduction in volume occurs,the final volume of the air will be approximately ......... $mL$.

Medium

View Solution

Which of the following has the maximum mass?

Medium

View Solution

Mole fraction of $O_2$ in an $O_2$ and $O_3$ mixture is $0.25$. Hence,the percentage concentration $\left( \frac{w}{W}\% \right)$ of $O_2$ in the mixture is:

Medium

View Solution

$A$ metal oxide contains $75 \%$ metal by mass. If the vapour density of the metal chloride is $89$,what is the atomic weight of the metal?

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The number of moles of solute present in the solutions of $I$,$II$ and $III$ is respectively:$I$. $500 \ mL$ of $0.2 \ M \ NaOH$$II$. $200 \ mL$ of $0.1 \ N \ H_2SO_4$$III$. $6 \ g$ of urea in $1 \ kg$ of water

Similar Questions

$4 \ g$ equimolar mixture of $NaOH$ and $Na_{2}CO_{3}$ contains $x \ g$ of $NaOH$ and $y \ g$ of $Na_{2}CO_{3}$. The value of $x$ is $..... \ g$. (Nearest integer)

If one liter of air is repeatedly passed over heated copper and magnesium until no further reduction in volume occurs,the final volume of the air will be approximately ......... $mL$.

Which of the following has the maximum mass?

Mole fraction of $O_2$ in an $O_2$ and $O_3$ mixture is $0.25$. Hence,the percentage concentration $\left( \frac{w}{W}\% \right)$ of $O_2$ in the mixture is:

$A$ metal oxide contains $75 \%$ metal by mass. If the vapour density of the metal chloride is $89$,what is the atomic weight of the metal?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The number of moles of solute present in the solutions of $I$,$II$ and $III$ is respectively:
$I$. $500 \ mL$ of $0.2 \ M \ NaOH$
$II$. $200 \ mL$ of $0.1 \ N \ H_2SO_4$
$III$. $6 \ g$ of urea in $1 \ kg$ of water