(C) The molarity $(M)$ of a solution is defined as the number of moles of solute $(n)$ per liter of solution ($V$ in $L$): $M = \frac{n}{V(L)}$ Given:

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(C) The molarity $(M)$ of a solution is defined as the number of moles of solute $(n)$ per liter of solution ($V$ in $L$): $M = \frac{n}{V(L)}$ Given: $M = 0.5 \ M$ $V = 2 \ L$ Substituting the values into the formula: $0.5 = \frac{n}{2}$ $n = 0.5 \times 2 = 1 \ mol$ Therefore,the number of moles is $1$.