The number of persons joining a cinema ticket counter in a minute follows a Poisson distribution with parameter $\lambda = 6$. The probability that at least one and at most five persons join the queue in a particular minute is:

  • A
    $e^{-6 \times 6}(25.48)$
  • B
    $e^{-6}\left(\frac{6}{2}+\frac{6^3}{3 !}+\frac{6^4}{4 !}\right)$
  • C
    $6 \times e^{-6}(29.8)$
  • D
    $e^{-6}\left(6+\frac{6^2}{2}+\frac{6^3}{3 !}+\frac{6^4}{4 !}\right)$

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