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(D) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$.Monochlorination can occur at four different types of hydrogen atoms:$1$. At $C-1$

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$2$

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(D) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$.Monochlorination can occur at four different types of hydrogen atoms:$1$. At $C-1$ (terminal methyl group): $Cl-CH_2-CH(CH_3)-CH_2-CH_3$. This molecule has a chiral center at $C-2$,so it exists as a pair of enantiomers.$2$. At $C-2$: $CH_3-CCl(CH_3)-CH_2-CH_3$. This molecule is achiral.$3$. At $C-3$: $CH_3-CH(CH_3)-CHCl-CH_3$. This molecule has a chiral center at $C-3$,so it exists as a pair of enantiomers.$4$. At $C-4$: $CH_3-CH(CH_3)-CH_2-CH_2Cl$. This molecule is achiral.Thus,there are $2$ chiral products,each forming an enantiomeric pair. Therefore,the total number of enantiomeric pairs is $2$.

The number of possible enantiomeric pairs that can be produced during monochlorination of $2$-methylbutane is

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