The number of possible tripeptides formed inv | vedclass

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(A) tripeptide is formed by the combination of $3$ amino acids.Since we have $3$ distinct amino acids ($ala$, $gly$, $val$) and each is used exactly o

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$6$

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(A) tripeptide is formed by the combination of $3$ amino acids.Since we have $3$ distinct amino acids ($ala$, $gly$, $val$) and each is used exactly once, the number of possible arrangements is given by the permutation of $3$ items taken $3$ at a time.Number of arrangements = $3! = 3 	imes 2 	imes 1 = 6$.The possible tripeptides are:$1. Gly-ala-val$$2. Gly-val-ala$$3. Val-gly-ala$$4. Val-ala-gly$$5. Ala-val-gly$$6. Ala-gly-val$Total tripeptides = $6$.

The number of possible tripeptides formed involving alanine $(ala)$, glycine $(gly)$, and valine $(val)$, where no amino acid has been used more than once is:

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