The number of significant figures in $6.25 \times 10^5$ is

  • A
    $11$
  • B
    $6$
  • C
    $4$
  • D
    $3$

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Similar Questions

$Assertion$ : The number of significant figures depends on the least count of the measuring instrument.
$Reason$ : Significant figures define the accuracy of the measuring instrument.

Three measurements are made as $18.425 \, cm$,$7.21 \, cm$,and $5.0 \, cm$. The addition should be written as ........ $cm$.

Match the numbers in Column-$I$ with the number of significant figures in Column-$II$.
Column-$I$ Column-$II$
$(1)$ $2.85 \times 10^{26} \ kg$ $(a)$ $1$
$(2)$ $0.009 \ m^2$ $(b)$ $2$
$(3)$ $0.060 \ s$ $(c)$ $3$

State the number of significant figures in the following:
$(a)$ $0.007 \;m^{2}$
$(b)$ $2.64 \times 10^{24} \;kg$
$(c)$ $0.2370 \;g \;cm^{-3}$
$(d)$ $6.320 \;J$
$(e)$ $6.032 \;N \;m^{-2}$
$(f)$ $0.0006032 \;m^{2}$

The length,breadth,and thickness of a block are given by $l = 12 \, cm$,$b = 6 \, cm$,and $t = 2.45 \, cm$. The volume of the block according to the rules of significant figures should be:

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