The number of tertiary carbon atoms in the compound $(CH_3)_2CHCH_2C(CH_3)_3$ is

  • A
    $2$
  • B
    $3$
  • C
    $1$
  • D
    $4$

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Similar Questions

The reactions which produce alcohol as the product are:
$A$. $CH_{4} + O_{2} \xrightarrow{Mo_{2}O_{3}}$
$B$. $2CH_{3}CH_{3} + 3O_{2} \xrightarrow[\Delta]{(CH_{3}COO)_{2}Mn}$
$C$. $(CH_{3})_{3}CH \xrightarrow{KMnO_{4}}$
$D$. $2CH_{4} + O_{2} \xrightarrow{Cu/523 \ K/100 \ atm.}$
$E$. $CH_{3}CH=CHCH_{3} \xrightarrow{KMnO_{4}/H^{+}}$
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When sodium propionate is heated with soda lime,the main product is

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