The number of unit cells present in $39 \ g$ of potassium if it crystallizes as body-centered cubic $(BCC)$ is ($N = \text{Avogadro number}$,$\text{At. wt. of potassium} = 39$).
- A$\frac{N}{4}$
- B$\frac{N}{2}$
- C$\frac{N}{3}$
- D$N$
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