The number of unpaired electrons in Fe^{3+} ( | vedclass

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(A) The atomic number of $Fe$ is $26$. The electronic configuration of $Fe$ is $[Ar] \ 3d^6 4s^2$.To form $Fe^{3+}$,we remove $3$ electrons (two from

Vedclass · Accepted Answer

$5$

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(A) The atomic number of $Fe$ is $26$. The electronic configuration of $Fe$ is $[Ar] \ 3d^6 4s^2$.To form $Fe^{3+}$,we remove $3$ electrons (two from $4s$ and one from $3d$):$Fe^{3+} = [Ar] \ 3d^5 4s^0$.The $3d$ subshell has $5$ orbitals,each containing one unpaired electron according to Hund's rule.Therefore,the total number of unpaired electrons is $5$.

The number of unpaired electrons in $Fe^{3+}$ $(Z = 26)$ is:

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