The number of unpaired electrons in a ferrous | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The atomic number of iron $(Fe)$ is $26$.The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms a ferrous ion $(Fe^{2+})$,it los

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The atomic number of iron $(Fe)$ is $26$.The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms a ferrous ion $(Fe^{2+})$,it loses two electrons from the $4s$ orbital.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the $3d$ subshell,there are $5$ orbitals. According to Hund's rule,the $6$ electrons are filled as follows: $4$ orbitals contain $1$ electron each,and $1$ orbital contains $2$ electrons.Therefore,the number of unpaired electrons in $Fe^{2+}$ is $4$.

The number of unpaired electrons in a ferrous ion $(Fe^{2+})$ is:

Similar Questions

The atomic number of an element is $35$ and its mass number is $81$. The number of electrons in the outermost shell is:

The $3p$ orbital has ........

Which of the following is correct on the basis of Hund's rule but does not follow Pauli's principle?

The electrons,identified by quantum numbers $n$ and $l$ as $(i) n = 4, l = 1$,$(ii) n = 4, l = 0$,$(iii) n = 3, l = 2$,$(iv) n = 3, l = 1$,can be placed in order of increasing energy,from the lowest to highest,as:

Krypton $(_{36}Kr)$ has the electronic configuration $[Ar] 4s^2 3d^{10} 4p^6$. The $37^{th}$ electron will go into which of the following subshells?

Vedclass Test Series

Exam Paper Generator

Online Exam Module