The number of ways of arranging all the letters of the word $PERFECTION$ such that there must be exactly two consonants between any two vowels is

  • A
    $4! \times 6!$
  • B
    $3! \times 6!$
  • C
    $2! \times 3! \times 6!$
  • D
    $4! \times 5!$

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