The numerical aperture of a microscope is 0.1 | vedclass

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(D) The limit of resolution $(x)$ of a microscope is given by the formula: $x = \frac{0.61 \lambda}{NA}$, where $NA$ is the numerical aperture.Given:$

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$3.0$

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(D) The limit of resolution $(x)$ of a microscope is given by the formula: $x = \frac{0.61 \lambda}{NA}$, where $NA$ is the numerical aperture.Given:$\lambda = 600 \, nm = 600 	imes 10^{-9} \, m = 6 	imes 10^{-7} \, m$$NA = 0.12$Substituting the values into the formula:$x = \frac{0.61 	imes 6 	imes 10^{-7}}{0.12}$$x = \frac{3.66 	imes 10^{-7}}{0.12}$$x = 30.5 	imes 10^{-7} \, m = 3.05 	imes 10^{-6} \, m$Since $1 \, \mu m = 10^{-6} \, m$, we have $x \approx 3.05 \, \mu m$.Rounding to the nearest given option, the limit of resolution is $3.0 \, \mu m$.

The numerical aperture of a microscope is $0.12$, and the wavelength of light used is $600 \, nm$. Then its limit of resolution will be nearly $............. \, \mu m$.

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